Math, asked by kamranrasheed4394, 7 months ago

When 6x square +kx+7is divided by x-2 ,it leaves the remainder 13 . Find it values of k

Answers

Answered by falaquejahan1928
1

Step-by-step explanation:

6x²+kx+7

X-2=0,x=2 remainder = 13

= f(2) = 6*2²+k*2+7 = 13

= 24+2k+7=13

= 2k=31-13

= 2k = 18

= k = 9

Hopes it will be helpful for you

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