When 6x square +kx+7is divided by x-2 ,it leaves the remainder 13 . Find it values of k
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Step-by-step explanation:
6x²+kx+7
X-2=0,x=2 remainder = 13
= f(2) = 6*2²+k*2+7 = 13
= 24+2k+7=13
= 2k=31-13
= 2k = 18
= k = 9
Hopes it will be helpful for you
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