when 8.4 g of NaHCO3 is added to a solution of CH3COOH weighing 20g. it is observed that 4.4 g of CO2 is released into atmosphere and a residue is left behind. Calculate the mass of residue by applying law of conservation of mass.
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Law of conservation of mass states that mass is neither created nor destroyed i.e. The mass of reactants which we found before chemical reaction is same as the mass of products that we will find after chemical reaction within a closed system.
Therefore, Mass of reactants = Mass of products
Given,
Mass of NaHCO3 = 8.4gm
Mass of CH3COOH = 20gm.
Total mass of products = 8.4+20 = 28.4gm.
Mass of CO2 released = 4.4gm
Let mass of residue be x
Total mass of reactants = 4.4+x
According to law of conservation of mass ,
28.4=4.4+x
Therefore, x = 28.4 - 4.4 =24gm.
Therefore, mass of residue is 24gm.
Therefore, Mass of reactants = Mass of products
Given,
Mass of NaHCO3 = 8.4gm
Mass of CH3COOH = 20gm.
Total mass of products = 8.4+20 = 28.4gm.
Mass of CO2 released = 4.4gm
Let mass of residue be x
Total mass of reactants = 4.4+x
According to law of conservation of mass ,
28.4=4.4+x
Therefore, x = 28.4 - 4.4 =24gm.
Therefore, mass of residue is 24gm.
blacl:
thanks, now i understand this question
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