when 9 is added to the numerator and 10 is subtracted from the denominator of a fraction the fraction becomes 4 by 3 when 5 is added to the denominator of the fraction and 1 is subtracted from its numerator the fraction = 1 by 3 find the fraction
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let the numerator be x
related denominator b y
1st condition
x+9/y-10=4/3
3 (x+9)=4 (y-10)
=>3x+27=4y-40
=>3x-4y=-67 ..........(1)
2nd condition
x-1/y+5=1/3
=>3 (x-1)=y+5
=>3x-3=y+5
=>3x-y=8
next Solved in photo....
related denominator b y
1st condition
x+9/y-10=4/3
3 (x+9)=4 (y-10)
=>3x+27=4y-40
=>3x-4y=-67 ..........(1)
2nd condition
x-1/y+5=1/3
=>3 (x-1)=y+5
=>3x-3=y+5
=>3x-y=8
next Solved in photo....
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