Question

When a 12 N force acts on 3 kg mass for a second . The change in velocity is

Answer 1

The change in velocity is 4 m/s.

Explanation:

The impulse is given as

I =Ft

The rate of change of momentum is equal to the impulse and mathematically given as

$m(v_f-v_i)=Ft$

Here, m is the mass of the body, v_f is the velocity of the body after impule is applied and v_i  is the initial velocity of the body, F is the force acts on the body for a time t.

Given F = 12 N,  m =  3 kg and t = 1 s.

Substitute the given values, we get

$3kg(v_f-v_i)=12N\times1s$

$v_f-v_i=\frac{12N}{3kg}$

$v_f-v_i=4m/s$

Thus, the change in velocity is 4 m/s.

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