When a 12 volt battery is connected across a unknown resistor there is a current of 2.5 milliamphere in the in the circuit find the value of the resistance of the system?
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the answer is 4800 ohms . formula used was v = I × r.
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According to Ohm’s law,
V = IR
=v/I
Here, V = 12 V and I = 2.5 mA = 0.0025 A Therefore,
=12/ 0.0025 = 4800 Ω = 4.8 kΩ
I hope, this will help you___❤❤
Thank you
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