Question

When a 120 force acts on 3 kg mass for a second, the
Changes is m/s​

Answer 1

Answer:

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v=u+at

a=  

t

(v−u)

​  

 

  =  

25

(3.5−2)

​  

=0.06m/s  

2

 

As per Newton's second law of motion, force is given as:

F=ma

   =3×0.06=0.18N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

Explanation:

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