when a 12v batery is connected across an unknown resistor,there is a current of 2.5 ma in the circuit.Find the value of resistance of the resistor
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1
V ≈ 12v
I ≈ 2.5mA ≈ 2.5×10 raised to -3
According to ohm's law V ≈ IR
⇒ R ≈ V/I
R ≈ 12/2.5×10 raised to -3
R ≈ 4.8 × 10³ohms
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6
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According to Ohm’s law,
V = IR
=v/I
Here, V = 12 V and I = 2.5 mA = 0.0025 A Therefore,
=12/ 0.0025 = 4800 Ω = 4.8 kΩ
I hope, this will help you___❤❤
Thank you
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