Question

When a 12V battery is connected across an
unknown resistor, there is a current of 2.5 mA in
the circuit. Find the value of the resistance of the
resistor.
[NCERT
​

Answer 1

Answer:

Given: V=12 V

I=2.5 mA

Let the resistance be R

By Ohm's Law,

V=IR

12=2.5×10

−3

R

R=4.8×10

3

Ω

Explanation:

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Answer 2

Answer:

Given, V=12

I = 2.5 mA

Let the resistance will be R

By ohm's law,

$v = ir$

$12 = 2.5 \times {10}^{ - 3} r$

$r = 4.8 \times {10}^{ - 3}$

Explanation:

So the answer is 4.8×10 to the power of -3 ampheres.

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