When a 22 ohms resistance is connected across its terminals a potential difference 2.2V is produced. Find the internal resistance and lost volt of the cell..
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1)Cell and external resistor are connected directly,
R(eq)=r+R
0.1+3.9=4.0 ohm
2)Current in circuit,
I=E/R
2/4.0=1/2=0.5A
3) Potential difference across terminal of a cell,
V=E-Ir
=2-0.5*0.1
1.95V
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