Question

when a = 3 , b=0 and C = - 2 find the value a^3 + b^3 + C^3 - 3abc​

Answer 1

Answer:

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Step-by-step explanation:

$a^3 + b^3 + c^3 - 3abc \\ \\ {(3)}^{3} + (0) {}^{3} + {( - 2)}^{3} - 3(3)(0)( - 2) \\ \\ 9 + 0 + ( - 8) - 0 \\ \\ 9 + 0 - 8 - 0 \\ \\ 9 - 8 \\ \\ 1$