Question

When a 4 Ω resistor is connected across the terminals of a 2 V battery, the number of coulombs passing through the resistor per second is:​
Quickly as possible

Answer 1

Answer:

$i = \frac{v}{r} \\ i = \frac{2}{4} \\ = \frac{1}{2} \\ = 0.5 \: ampere \\ = 0.5 \: coulombs \: per \: second$

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Answer 2

Answer:

1/2 or 0.5 C is passing through the resistor per second

Explanation:

For explanation kindly refer to attached file.

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