when a 4kg rifle is fired, the 10g bullet receives an acceleration of 3*10^6 cm/s^2. the magnitude of force acting on rifle
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Answered by
198
F = ma
= 10 g × 3 × 10^6 cm/s^2
= 3 × 10^7 dynes
= 300 × 10^5 dynes
= 300 N
Force acting on rifle is 300 N
= 10 g × 3 × 10^6 cm/s^2
= 3 × 10^7 dynes
= 300 × 10^5 dynes
= 300 N
Force acting on rifle is 300 N
Answered by
19
Answer:
F=ma
F=3×10^6×10dyne=300N
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