Question

When a 5.0 gram sample of naphthalene (C10H8) is burned in a bomb calorimeter, the temperature of the calorimeter increases from 10.5 C to 16.2 C. Assuming the heat capacity of the calorimeter is 8.2 J/C...
What was dH/q/enthalpy change for the reaction?​

Answer 1

Answer:

Explanation:

bomb calorimeter formula

cdelt/m/M

8.2(5.7) / 5/128

128*8.2*5.7/5

1196.5 j

it is delta u

because nothing information is given to us, so we use assume constant volume

now apply delh for chemical reactions which is delu + delta ngrt

now write reaction of combustion of c10h8

c10h8+ 12o2 = 10co2+4h2o

here delta ng = -2

so del h = del u + del ngrt

=1196.5-2*8.314*16.2

=927.12 j