When a 9 V battery is connected across an unknown reisstor, there is a current of 3 mA in circut, find the value of the resistance of the resistor.
Answers
Answer:
The resistance across the circuit is 3000 ohms
Explanation:
Given :
- Potential difference or the voltage across the battery = 9 Volts
- Current flowing through the circuit = 3 MA
To find :
- Value of resistance across the circuit
Using ohms law which says : V=IR
3 MA = 3 × 10^-3
Substituting the values :
9= 3×10^-3×R
9/3=10^-3×R
3= 1/1000 ×R
3000 = R
Resistance is equal to 3000 ohms
_______________________________
✰Question ✰
▪When a 9 V battery is connected across an unknown reisstor, there is a current of 3 mA in circut, find the value of the resistance of the resistor.
_______________________________
Given:-
- Potential difference (V) =9volts
- Current carrying through circuit (I) =3MA
∴ 3MA =3×10^-3
To Find:-
▪ Resistance (R) of the resistor.
Solution :-
According to Ohm's Law
☛ V =IR
☛ 9=3×10^-3×R
☛ 9×10^3/3 =R
☛ R = 9× 1000/3
☛ R = 3000 ohm.
∴The resistance of the resistor is 3000 oh.
_______________________________
More Information!!!!!!!
☛ The Ohm's law states that the potential difference across the ends of a given metallic wire in an electric circuit is directly proportional to the current flowing through it, provide its temperature remain in the same.
V ∝ I............. (i)
V/I= R (constant)............(ii)
From equation (i) and (ii) we get
☛ V=IR