Question

when A and B are 2 mutually exclusive events ,are the values P(A)=0.6 and P(A interegation B')=0.5 consistent ? why?​

Answer 1

Step-by-step explanation:

since A and B are mutually exclusive, therefore A intersection B is ∅. 

Hence, P( A ∪ B ) = P(A) + P(B). 

hence, P(A∪B) = 0.5 + 0.4 = 0.9

Now, P(A' ∩ B') = P(A∪B)' [ using DeMorgan's Law ]

= 1 - P(A∪B) = 1-0.9 = 0.1

Answer 2

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