Physics, asked by DeltaSkull, 1 year ago

When a ball is thrown vertically upwards, it goes through a distance of 19.6m. Find the initial velocity of the ball and the time taken by it to rise to the highest point.​

Answers

Answered by abhisheksharma281203
0

Answer: Initial velocity is 14 m/s and time taken to reach is 1.4 second.

Explanation:

Attachments:
Answered by Anonymous
2

Answer:

2 seconds

Explanation:

Distance travelled by the ball = 19.6m

Let the initial velocity be = u m/s

Time taken to rise to the highest point = t second

Final velocity at the highest point = 0

g = -9.8 m/s²

Thus.

d = (v² - u²)/2a

= 19.6 = (0 - u²)/2 × (-9.8)

= 19.6 = u²/19.6

= u² = 19.6×19.6

= u = 19.6 m/s

According to first equation of motion -

v = u + at

= 0 = 19.6 - 9.8t

= 9.8t = 19.6

= t = 19.6/9.8

= t = 2s

Therefore, the time taken to rise to the highest point is 2s

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