when a Boat is partially immersed in water it displaces 600 kg of water how much is the buoyant force acting on the boat in Newtons where g is equals to 10 M per second square
Answers
Answered by
29
Buoyant force = weight of liquid displaced.
mass of water displaced = 600 kg
weight = mg = 600 × 10 = 6000 N
So buoyant force = 6000 N
__________________________
If you are wondering how buoyant force = weight of liquid displaced?
The formula: buoyant force = pgV
=> buoyant force = pV × g
=> buoyant force = m × g
=> buoyant force = mg
=> buoyant force = weight of liquid displaced
mass of water displaced = 600 kg
weight = mg = 600 × 10 = 6000 N
So buoyant force = 6000 N
__________________________
If you are wondering how buoyant force = weight of liquid displaced?
The formula: buoyant force = pgV
=> buoyant force = pV × g
=> buoyant force = m × g
=> buoyant force = mg
=> buoyant force = weight of liquid displaced
olnlyguesses:
what is p there sir
Answered by
0
Buoyant force = weight of liquid displaced.
mass of water displaced = 600 kg
weight = mg = 600 × 10 = 6000 N
So buoyant force = 6000 N
__________________________
If you are wondering how buoyant force = weight of liquid displaced?
The formula: buoyant force = pgV
=> buoyant force = pV × g
=> buoyant force = m × g
=> buoyant force = mg
=> buoyant force = weight of liquid displaced.
HOPE SO IT WILL HELP.....
Similar questions