Physics, asked by Amreensiddique, 1 year ago

when a Boat is partially immersed in water it displaces 600 kg of water how much is the buoyant force acting on the boat in Newtons where g is equals to 10 M per second square

Answers

Answered by TPS
29
Buoyant force = weight of liquid displaced.

mass of water displaced = 600 kg

weight = mg = 600 × 10 = 6000 N

So buoyant force = 6000 N

__________________________

If you are wondering how buoyant force = weight of liquid displaced?

The formula: buoyant force = pgV

=> buoyant force = pV × g

=> buoyant force = m × g

=> buoyant force = mg

=> buoyant force = weight of liquid displaced

olnlyguesses: what is p there sir
TPS: density... p looks like rho.. so used it...
olnlyguesses: thanks
TPS: density × volume = mass...... mass × g = weight
Answered by BrainlyFlash156
0

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Buoyant force = weight of liquid displaced.

mass of water displaced = 600 kg

weight = mg = 600 × 10 = 6000 N

So buoyant force = 6000 N

__________________________

If you are wondering how buoyant force = weight of liquid displaced?

The formula: buoyant force = pgV

=> buoyant force = pV × g

=> buoyant force = m × g

=> buoyant force = mg

=> buoyant force = weight of liquid displaced.

HOPE SO IT WILL HELP.....

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