Question

when a body covers first one third distance with speed 1m/s the second one third distance with speed2m/s and last one third distance with speed 3m/s then average speed is​

Answer 1

Answer:

11/6m/s (pardon any calculation mistakes)

Explanation:

avg speed = total dis/total time

so total distance = X

t1 = (1/3x)/1

t2=(1/3x)/2

t3=(1/3x)/3

because speeds are 1m/s, 2m/s and 3m/s resp.

therefore avg speed =

(t1+t2+t3)/x

=11/6m/s

Answer 2

Answer:

First one third distance = d/3 and speed is 1m/s

Second one third distance = d/3 and speed is 2m/s

Third one third distance = d/3 and speed is 3m/s

s = d/t

t = d/s

t1 = (d/3)/1

t2 = (d/3)/2

t3 = (d/3)/3

total time = (d/3)/1 + (d/3)/2 + (d/3)/3 = 11d/18

total distance = d

speed av = total distance / total time

= d / 11d/18

= 18d/11

= 1.64m/s

Explanation: