Question

.When a body falls freely towards the earth, then its total energy
increases

(b) decreases

(c) remains constant

(d) first increases and then decreases​

Answer 1

Answer:

c) Since, total energy of the system is always conserved, so when a body falls freely towards the earth, then its total energy remains constant i.e., the sum of the potential energy and kinetic energy of the body would be same at all points.

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Explanation:

Answer 2

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Answer:

(c) remains constant

Explanation:

Since the total energy of the system is always conserved, so when a body falls freely towards the earth, then its total energy remains constant i.e., the sum of the potential energy and kinetic energy of the body would be the same at all points.

KE = $\frac{1}{2}$ m$v^{2}$

PE = mgh

at point A

v = 0

TE = KE + PE

TE = 0 + mgh

TE = mgh      (i)

at point B

h = $\frac{h}{2}$

$v^{2}$ - $u^{2}$ = 2g$\frac{h}{2}$

v = $\sqrt{gh}$

TE = KE + PE

TE = $\frac{1}{2}$m$\sqrt{gh} ^{2}$ + $\frac{mgh}{2}$

TE = $\frac{1}{2}$mgh + $\frac{mgh}{2}$

TE = mgh      (ii)

From (i) and (ii) we conclude that

Total energy remains constant.