Question

When a body is moving in circular path with acceleration a if its velocity gets doubled find the ratio of acceleration after n before the change?

Answer 1

when an object moves in circular path with constant speed

then it acceleration is given as

$a = \frac{v^2}{R}$

now we have

$a_1 = \frac{v^2}{R}$

when speed is doubled then acceleration is given as

$a_2 = \frac{(2v)^2}{R}$

$a_2 = \frac{4v^2}{R}$

now the ratio of final and initial acceleration will be

$\frac{a_2}{a_1} = \frac{4v^2/R}{v^2/R}$

so it will be

$\frac{a_2}{a_1} = 4 : 1$

so the ratio of acceleration will be 4 : 1

Answer 2

4:1 is the best answer