Question

When a boy was 25 years old, his father began his journey into space. The father returned when the son was 55 years old. At what velocity does the father return and see the difference between his age and the age of the son is 10 years less than before?
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Answer 1

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When a boy was 25 years old, his father began his journey into space. The father returned when the son was 55 years old. At what velocity does the father return and see the difference between his age and the age of the son is 10 years less than before?

$\bigstar \: \boxed{\sf{\color{purple}{Answer:}}}$

Let,

Let the age of son be x.

Thus, age of father is 4x.

After 5 yrs,

After 5 years, their ages will be x+5 and 4x+5 years respectively.

As per the question, we have

4x+5=3(x+5)

⇒4x+5=3x+15

⇒x=10

Step by step solution :

Age of father will be 4x=4×10=40 years.

Thus when son is 10 years old, father is 40 years.

Hence, Verified!

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$\sf\red{Thank\:you!}$

Answer 2

Question:

When a boy was 25 years old, his father began his journey into space. The father returned when the son was 55 years old. At what velocity does the father return and see the difference between his age and the age of the son is 10 years less than before?

When a boy was 25 years old, his father began his journey into space. The father returned when the son was 55 years old. At what velocity does the father return and see the difference between his age and the age of the son is 10 years less than before?

Answer:

Father will be 40 yrs old when his son will be 10 years old.

Explanation:

Let the age of boy be = x

Let the age of father be = 4x

After 5 years there ages.....

Son = x + 5 , Father = 4x + 5

So now,

= 4x + 5 = 3(x + 5)

= 4x + 5 = 3x + 15

= x = 10

• Hence, son's age will be 10 years and father's age will be 4x = 4 × 10 = 40 years