Question

When a byte of data is write to the memory address A4673H, the state of the control signal which occur in this cycle are:
A) BHE#=0, A0=1, M/IO#=1, DT/R#=1, RD#=1, WR#=0, DEN#=0

B) BHE#=1, A0=0, M/IO#=0, DT/R#=1, RD#=0, WR#=1, DEN#=0.

C) BHE#=0, A0=1, M/IO#=0, DT/R#=1, RD#=1, WR#=0, DEN#=0

D) BHE#=1, A0=0, M/10#=0, DT/R#=1, RD#=0, WR#=0, DEN#=1.​

Answer 1

Intel 8086 is a 16-bit HMOS microprocessor. It is available in 40 pin DIP chip. It uses a 5V DC supply for its operation. The 8086 uses 20-line address bus. It has a 16-line data bus. The 20 lines of the address bus operate in multiplexed mode. The 16-low order address bus lines have been multiplexed with data and 4 high-order address bus lines have been multiplexed with status signals. 

AD0-AD15 : Address/Data bus. These are low order address bus. They are multiplexed with data. When AD lines are used to transmit memory address the symbol A is used instead of AD, for example A0-A15. When data are transmitted over AD lines the symbol D is used in place of AD, for example D0-D7, D8-D15 or D0-D15.