Question

When a capillary tube is dipped in a liquid, the liquid rises to a height h in the tube. The free liquid surface inside, the tube is hemispherical in shape. The tube is now pushed down so that the height of the tube outside the liquid is less than h. Then

Answer 1

Explanation:

Consider a capillary tube of radius r immersed in a liquid of surface tension T and density ρ. The height to which the liquid will rise in the capillary tube is given as

rρg

2Tcosθ

=

Rρg

2T

or

hR=

ρg

2T

which is a constant.

Thus we get

h

1

R

1

=h

2

R

2