Question

When a car driver travelling at a speed of 10 m/s applies brakes and brings the car to rest in 20 s, then the retardation will be:

Answer 1

Answer:

-0.5 m/s²

Explanation:

given,

v = 0 m/s  (since the car comes to rest)

u = 10 m/s

t = 20 seconds

acceleration = (v-u)/t

                    = (0-10)/20

                    = -1/2

acceleration = -0.5 m/s²

We know that, negative acceleration is also known as deceleration or retardation.

Therefore,

deceleration/retardation = 0.5 m/s²

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Answer 2

Question :-

When a car driver travelling at a speed of 10 m/s applies brakes and brings the car to rest in 20 s, the retardation will be

Given :-

• u = 10 m/s
• v = 0 m/s
• t = 20 s

To find :-

Retardation

Solution :-

Substituting the values in 1st equation of motion :-

v = u + at

0 = 20 + 20a

20a = -20

a = -1 m/s²

Retardation = 1 m/s²