Question

when a car driver travelling at a speed of 10 m/s applies brakes and brings the car to rest in 20s, then retardation will be

Answer 1

Answer:

• ❑ Initial Velocity (u) = 10 m/s

• ❑ Final Velocity (v) = 0 m/s

• ❑ Time taken (t) = 20 seconds

❍ By Using 1st equation of motion :]

• v = u + at

❴ where, v = Final Velocity, u = Initial Velocity, t = Time taken and a = Acceleration ❵

• Putting in the values :]

➥ v = u + at

➥ 0 = 10 + a(20)

➥ 0 = 10 + 20a

➥ 20a = 10

➥ a = 10/20

➥ a = -0.5 m/s²

⛬ Acceleration produced is -0.5 m/s² and as we know that, Retardation is nothing but negative Acceleration So, Retardation produced by the car is 0.5 m/s².

Answer 2

Aɴsᴡᴇʀ:

• Retardation produced by the car = 0.5 m/s²

Gɪᴠᴇɴ:

• When a car driver travelling at a speed of 10 m/s applies brakes and brings the car to rest in 20seconds.

Nᴇᴇᴅ Tᴏ Fɪɴᴅ:

• Retardation produced by the car = ?

Solution:

Aᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ᴛʜᴇ ғɪʀsᴛ ᴇǫᴜᴀᴛɪᴏɴ ᴏғ ᴍᴏᴛɪᴏɴ:

• v = u + at

Pᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇs:

➜ 0 = 10 + a × 20

➜ 0 = 10 + 20a

➜ 20a = 10

➜ Acceleration = 10/20

➜ Acceleration = -0.5 m/s²

Tʜᴇʀᴇғᴏʀᴇ:

• Retardation produced by the car is 0.5 m/s².

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