When a car driver travelling at a speed of 20
m/s applies brakes and brings the car to rest
in 40 s, then the acceleration will be:
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Answer:
- a car driver travelling at speed = 20m/s
- a car driver travelling at speed = 20m/s intial velocity , u = 20 m/s
- a car driver travelling at speed = 20m/s intial velocity , u = 20 m/she applies brakes and brings the car to rest = 40s
- a car driver travelling at speed = 20m/s intial velocity , u = 20 m/she applies brakes and brings the car to rest = 40sso time taken to stop the car = 40s
- a car driver travelling at speed = 20m/s intial velocity , u = 20 m/she applies brakes and brings the car to rest = 40sso time taken to stop the car = 40swe have to find acceleration .
- a car driver travelling at speed = 20m/s intial velocity , u = 20 m/she applies brakes and brings the car to rest = 40sso time taken to stop the car = 40swe have to find acceleration . final velocity of car , v= 0
- a car driver travelling at speed = 20m/s intial velocity , u = 20 m/she applies brakes and brings the car to rest = 40sso time taken to stop the car = 40swe have to find acceleration . final velocity of car , v= 0 use formula = v=u + at
- a car driver travelling at speed = 20m/s intial velocity , u = 20 m/she applies brakes and brings the car to rest = 40sso time taken to stop the car = 40swe have to find acceleration . final velocity of car , v= 0 use formula = v=u + at 0 = 20 + a40
- a car driver travelling at speed = 20m/s intial velocity , u = 20 m/she applies brakes and brings the car to rest = 40sso time taken to stop the car = 40swe have to find acceleration . final velocity of car , v= 0 use formula = v=u + at 0 = 20 + a40a= 40 / 20 = - 1/2 m/ s²[ hereative sing shows acceleration] .
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