Question

when a car driver trevlling at a speed of 10 m/s aplies break and bring the car to rest in 20s then the retardation will be​

Answer 1

Answer:

2m/second square

Explanation:

may this would help u

Answer 2

Answer:

2 m.

Explanation:

Using the equation of motion

V = U + at

Your v = 0 m/sec

U = 10 m/sec

t = 20 sec

a in this case negative acceleration i.e. deceleration = ?

so substituong in the equation of motion mentioned above,

Deceleration = 0.5 m/sec^2..

HENCE 20/10 = 2m RETARDATION.