Question

When a car is stopped by applying break it stops after traveling a distance of 100m if speed of car is halved same retarding acceleration is applied then it stop after traveling a distance of

Answer 1

AnswEr:-

From third equation of motion,

=> v² - u² = 2as

=> v.v-u.u=2a(100)...........(1)

for second part,

=>  v.v -u.u/4=2as...........(2)

By solving  equation (1) and (2),

=> s=25m

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