Chemistry, asked by karthirajen2004, 5 months ago

When a co-ordination compound CrCl3.4H2O is mixed with silvernitrate solution, one mole of silver chloride is precipitated per mole of the compound. There are no free solvent molecules in that compound. Assign the secondary valence to the metal and write the structural formula of the compound.

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Answered by Anonymous

1. When a coordination compound CrCl3 . 4H2O is mixed with silver nitrate solution, one mole of silver chloride is precipitated per mole of the compound. This shows CrCl3 . 4H2O complex compound contains one Cl® counter ion.

2. There are no free solvent molecules in CrCl3 . 4H2O compound, this shows water molecules are coordinated with central metal ion.

3. Therefore, coordination complex is [CrCl3 . 4H2O]Cl Secondary value of the central metal ion is 2Cl® and 4 H2O. Hence coordination number is 6.

4. Werner’s structure of [CrCl2 . (H2O)4]Cl

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When a co-ordination compound CrCl3.4H2O is mixed with silvernitrate solution, one mole of silver chloride is precipitated per mole of the compound. There are no free solvent molecules in that compound. Assign the secondary valence to the metal and write the structural formula of the compound.​

Answers

When a co-ordination compound CrCl3.4H2O is mixed with silvernitrate solution, one mole of silver chloride is precipitated per mole of the compound. There are no free solvent molecules in that compound. Assign the secondary valence to the metal and write the structural formula of the compound.