When a committee of 2 children is formed, out of 3 boys and 2 girls, state the probability that both children are boys.
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Answer:
The probability that both children are boys = 3/10
Explanation:
Boy =B
Girls=G
Total events =
- B1B2
- B1B3
- B1G1
- B1G2
- B2B3
- B2G1
- B2G2
- B3G1
- B3G2
- G1G2,
∴n=10
The Event that the committee contains only boys.
- B1B2
- B1B3
- B2B3
∴n(C)=3
P(E)= 3/10
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