Question

When a concave mirror is placed facing the Sun, the Sun’s rays converge to a point
10 cm from the mirror.Now, if you place a 2 cm long candles flame 20 away on

the principal axis of the mirror, where would you place a screen to obtain the image

of the candle? What would see the size of the image? Draw a ray diagram to justify

your answer.​

Answer 1

Answer:

hey dear ...

Converge to a point =10 cm

flame of candel = 20cm

enlarge in size .

image is errect .

Answer 2

Explanation:

hence ,

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)1/v = 1/20 - 1/10

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)1/v = 1/20 - 1/10v = -20 cm

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)1/v = 1/20 - 1/10v = -20 cmhence position of image is also 20cm in side of object .

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)1/v = 1/20 - 1/10v = -20 cmhence position of image is also 20cm in side of object .also ,

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)1/v = 1/20 - 1/10v = -20 cmhence position of image is also 20cm in side of object .also ,magnification = -v/u

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)1/v = 1/20 - 1/10v = -20 cmhence position of image is also 20cm in side of object .also ,magnification = -v/u= -(-20)/(-20)

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)1/v = 1/20 - 1/10v = -20 cmhence position of image is also 20cm in side of object .also ,magnification = -v/u= -(-20)/(-20)= -1

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)1/v = 1/20 - 1/10v = -20 cmhence position of image is also 20cm in side of object .also ,magnification = -v/u= -(-20)/(-20)= -1hence,

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)1/v = 1/20 - 1/10v = -20 cmhence position of image is also 20cm in side of object .also ,magnification = -v/u= -(-20)/(-20)= -1hence,magnification = -1

hence ,focal length of mirror = -10 cm { focal length negative due to concave mirror }now,use mirror formula,1/v + 1/u =1/f1/v + 1/(-20) = 1/(-10)1/v = 1/20 - 1/10v = -20 cmhence position of image is also 20cm in side of object .also ,magnification = -v/u= -(-20)/(-20)= -1hence,magnification = -1this implies that size of object is equal to size of image . and negative sign of magnification indicate image formed real and inverted