when a current in a coil changes from 2 amp to 6 ampere in 0.05 sec .an emf of 8 volt is induced in the coil the coefficient of self induction of the coil is ?
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Answer:
0.2 henry
Induced e.m.f. ϵ=
dt
dϕ
=
dt
dBA
=A
0
dt
dB
=A
0
(
t
4B
0
−B
0
)=3A
0
B
0
/t
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