Question

When a current of (2.5 ± 0.5 ) A flows through a wire, it develops a potential difference of (20 ± 1) v. The resistance of the wire is ................. .
(A) (8 ± 2) Ω
(B) (8 ± 1.5) Ω
(C) (8 ± 0.5) Ω
(D) (8 ± 3) Ω

Answer 1

Answer:

The resistance of the wire is 8 ± 2 Ω

Explanation:

resistance of the wire  = Potential Difference / Current

=> Resistance of Wire =  ( 20  ± 1)/(2.5 ± 0.5)

= (20/2.5)  ±  (20/2.5) ( 1/20  + 0.5/2.5)

= 8  ± 8 (1/20  + 1/5)

= 8  ± 8(5/20)

=  8 ± 2

The resistance of the wire is 8 ± 2 Ω

Answer 2

Hope it's help you................