Physics, asked by mariyamhaidry82, 10 months ago

when a current of (5±0.5)A flows through a wire, it develops a potential difference of (40±1)V The resistance of the wire is ........
a (8±1.5 )Ω
b (8±0.5 )Ω
c (8±1 )Ω
d (8±2 )Ω​

Answers

Answered by mahek4823
6

Answer:

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Explanation:

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Attachments:
Answered by vijayhalder031
1

Concept Introduction:

Ohm's law: The strength of a direct current is directly proportional to the potential difference and inversely proportional to the resistance of the circuit.

Given: current of (5±0.5)A and potential difference of (40±1)V

To Find:

We have to find the value of, resistance of wire.

Solution:

According to the problem,

According to Ohm's Law V=IR

40=5 * R

R = 8Ω

And we know error gets added so 0.5+1=1.5

∴Resistance of the wire is (8±1.5 )Ω.

Final Answer:

The value of resistance of the wire is (8±1.5 )Ω.

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