When a die is rolled three times, the probabily sum of numbers is priime less than 10?
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Step-by-step explanation:
solution
One die is rolled.
Sample space ={1,2,3,4,5,6}
n (s) = 6.
Now
let event A be the sum of numbers is primeless than 10
A = { (1,2), (2,3),(3,4),(4,1),(6,1),(5,2) }
n(A) = 6
Now
P(A) = n(A) % n(s)
= 6%6
= 1
Probability of sum of numbers is prime less than 10 is 1
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