when a die is thrown find the probability of getting:a)A number less than or equal to 6 b)A number is greater than 6
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A) the nos. less than or equal to 6 in a die are:-1,2,3,4,5 & 6
Therefore, P(of getting a no less than or equal to 6)=no of outcomes/ total no of observations=6/6=1{ans}
B) A no greater than 6 in a die =0
Therefore, P(of getting a no greater than 6)=no of outcomes/ total no of observations=0/6=0
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a:P(A):6/6=1
b: P(E): 0/6=0
b: P(E): 0/6=0
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