when a die is thrown then the probability of getting of a prime number is
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There are 6 digits on a die (1, 2, 3, 4, 5, and 6). 1, 3 and 5 are prime numbers. The probability of a die coming up a prime numbers is equal to the number of prime numbers (Nprime = 3) divided by the total number of possible results (Ntotal = 6). Thus, p(prime number when tossing one die) = 3/6 = 0.5.
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