When a force applied to a body of mass 1 kg it's velocity changes from 10m/s to 20m/s in 2 sex. The rate of change of momentum of the body is: A) 5N B) 20N C) 10N D) zero
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9
m=1 kg
v=20 m/s
u=10 m/s
v-u=20-10=10 m/s
t=2 sec
rate of change of momentum=m(v-u)/t
=1(10)/2
=5N
v=20 m/s
u=10 m/s
v-u=20-10=10 m/s
t=2 sec
rate of change of momentum=m(v-u)/t
=1(10)/2
=5N
SAMARTHROCK456:
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Answered by
3
rate of change in momentum= mv-mu/t
=1×20-1×10/2
=10/2
=5kgm/s
=1×20-1×10/2
=10/2
=5kgm/s
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