Question

When a force is applied to a body of mass 2 kg , it's velocity changes from 20m/s to 30m/s in 2 sec. the rate of change of momentum of body is what?

Answer 1

Answer:10N

Explanation:

Rate of change in momentum =force

Acceleration=(v-u)/t

=(30-20)/2

=5m/s^2

F=ma

=2*5

=10

Answer 2

Answer:

The rate of change of momentum of the body is 10 N.

Explanation:

According to the question,

Given,

Mass = 2 kg

Time = 2 sec.

velocity change - 30m/s to 20 m/s

We know that,

Rate of change in momentum = force

Acceleration $= \frac{v-u}{t}$

Force $= ma$

so,

$a = \frac{v-u}{t}\\\\a = \frac{30-20}{2}\\\\a=5ms^{-2}$

Then, force is

$F = ma\\\\F = 2 X 5\\\\F = 10$

Hence, the rate of change of momentum of the body is 10 N.