Question

When a force is applied to the right at 80N and a force to the left at 145N, what is the net force?
In what direction?​

Answer 1

Given:-

▶ A force is applied to the right of a body of 80 N and at the left of 145 N.

To Find:-

▶ Net force.

Solution:-

Since, Force is a vector quantity which means it has both magnitude and direction.

Also, Let the forces be F1 = 80 N and F2 = 145 N and the angle between these two vectors is 180°

We know,

⇒ R = F1 + F2

⇒ R = √( F1² + F2² + 2F1F2cosϑ)

⇒ R = √( 80² + 145² + 2 × 80 × 145 × cos 180°)

⇒ R = √( 6400 + 21025 - 23200)

As, cos 180° = -1

⇒ R = √( 27425 - 23200)

⇒ R = √4225

⇒ R = 65 N

So, The Net Force is 65 N. Because the F2 vector's magnitude is greater than F1's and the angle b/w them is 180°. Hence, The resultant vector would be in the direction of the Force which is to the left.

Answer 2

Answer:

Given:-

▶ A force is applied to the right of a body of 80 N and at the left of 145 N.

To Find:-

▶ Net force.

Solution:-

Since, Force is a vector quantity which means it has both magnitude and direction.

Also, Let the forces be F1 = 80 N and F2 = 145 N and the angle between these two vectors is 180°

We know,

⇒ R = F1 + F2

⇒ R = √( F1² + F2² + 2F1F2cosϑ)

⇒ R = √( 80² + 145² + 2 × 80 × 145 × cos 180°)

⇒ R = √( 6400 + 21025 - 23200)

As, cos 180° = -1

⇒ R = √( 27425 - 23200)

⇒ R = √4225

⇒ R = 65 N

So, The Net Force is 65 N. Because the F2 vector's magnitude is greater than F1's and the angle b/w them is 180°. Hence, The resultant vector would be in the direction of the Force which is to the left.

Explanation:

Hope this answer will help you.