Question

When a force of 3 newton is applied to a wear;the lenghth becomes x
, when a force of 5 newton is applied on the same wear, the length becomes y, then what wil be the length , when a force of 7 newton is applied?Answer it quickly please...​

Answer 1

Answer:The answer's below please mark me brainliest.

Explanation:

$FL/A\triangle\L = Y\\ 3L/A (x-l) = 5L/A (y-l) = 7L/A (k-l)\\\frac{3}{x-l } = \frac{5}{y-l} = \frac{7}{k-l} \\ 7y-7l = 5k-5l\\k=7y-2l/5\\k=7x-4l/3$