Question

when a fraction is increased by 4 the fraction is increased by 2 upon 3 what is the denominator of the fraction​

Answer 1

Answer:

The fraction is -10/3 .

In improper form denominator is 3.

Answer 2

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The “increases by 23 " phrase has two meanings.

Let’s say it algebraically. I will give the names 'a' and 'b' to the numerator and denominator, and then I say your first sentence algebraically :

$\frac{a + 4}{b} = \frac{a}{b} + \frac{2}{3}$

That is certainly one meaning for what you said.

I clear the deonominator 'b' from both sides by multiplying both sides by 'b' :

$b( \frac{a + 4}{b}) = b( \frac{a}{b} + \frac{2}{3} )$

$a + 4 = a + \frac{2}{3}b$

So,

$4 = \frac{2}{3}b$

And,

$b = \frac{3}{2} \times 4 = 6$

And 'a' could have any value whatsoever.

But you might instead have meant that when 4 is added to the numerator, the fraction goes up by

$66 \frac{2}{3}$, which means :-

$\frac{a + 4}{b} = \frac{a}{b} + \frac{2}{3} \times ( \frac{a}{b} )$

So,

$\frac{a + 4}{b} = \frac{5}{3} \times \frac{a}{b}$

Again, clearing 'b' from the denominators of both sides by multiplying both sides by 'b' gives:

$a + 4 = \frac{5}{3} \times a$

$4 = \frac{5}{3} a - a$

$4 = a( \frac{5}{3} - 1)$

$a \: = \: \frac{4 \times 3}{2} = 6$

and 'b' could be anything except 0.

Now both interpretations would be true if a = 6 and b = 6 .