When a gaseous olefinic hydrocarbon is burnt
completely in excess of 02, a contraction in
volume equal to double to the volume of
hydrocarbon is noticed then hydrocarbon will be
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Let a olefinic hydrocarbon CxHy Acc. to question CxHy+O2=xCo2+y/2h20
contraction in volume =volume of hydrocarbon+volume of O2-volume of co2
so contraction volume=4+y/4Acc. to question 4+y/4=2 volume of hydrocarbon
soy=4
The given hydrocarbon is the gasoeus form so that contraction volume of Co2=contraction volume of h2o
And then x=y/2 x=2 Hydrocarbon is C2H4
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