When a hydrogen atom initially at rest emits a photon resulting a transition n=5 to n=1 its recoil speed?
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Hii dear,
# Answer- Recoil speed = 4.36 m/s.
# Explanation-
You'll already know that momentum is given by formula,
mv = h/λ ...(1)
For emission of photon during transition from n=5 to n=1, wavelength is given by,
1/λ = R(1/n1^2 - 1/n2^2)
1/λ = 1.097×10^7(1/1^2 - 1/5^2)
λ = 9.48 × 10^-8 m
Putting this in eqn (1)
mv = h/λ
1.6×10^-27 × v = 6.62×10^-34 / 9.48×10^-8
v = 4.36 m/s
Recoil speed of hydrogen atom is 4.36 m/s.
(standard values of R,h and m taken)
Hope that helped you...
# Answer- Recoil speed = 4.36 m/s.
# Explanation-
You'll already know that momentum is given by formula,
mv = h/λ ...(1)
For emission of photon during transition from n=5 to n=1, wavelength is given by,
1/λ = R(1/n1^2 - 1/n2^2)
1/λ = 1.097×10^7(1/1^2 - 1/5^2)
λ = 9.48 × 10^-8 m
Putting this in eqn (1)
mv = h/λ
1.6×10^-27 × v = 6.62×10^-34 / 9.48×10^-8
v = 4.36 m/s
Recoil speed of hydrogen atom is 4.36 m/s.
(standard values of R,h and m taken)
Hope that helped you...
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