When a load of 10 kg is hung from one end of a wire of length
5 m, the wire elongates by 5 mm . If the Young's modulus for
the material of the wire is 9.8 x 1010 N·m-2, then find the
area of cross section of the wire. [g = 9.8 m·s-2]
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Answer:
Correct answer is 100 m^2
Explanation:
Y=FL/A∆L
A=FL/Y∆L
=mgL/Y∆L
=10×9.8×5/9.8×100×5×10^-3
=10/100×10^-3
=10^4/10^2
A=100
I hope this answer will help you
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