when a load of 10 kg is hung from the core, then extension of 2 m is produced. then work done by restating force is
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work done = mg x l
work done = 10 x 9.8 x 2
w d = 196 J
work done = 10 x 9.8 x 2
w d = 196 J
mamoni2:
correct
Answered by
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when 10 kg mass is hung then extension produced is equal to 2 m
therefore,
force is applied equal to 10x9.8=98 N
where 9.8m/s^2 is acceleration due to gravity
then work = force×displacement
therefore work done=98×2=196joul
therefore,
force is applied equal to 10x9.8=98 N
where 9.8m/s^2 is acceleration due to gravity
then work = force×displacement
therefore work done=98×2=196joul
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