When a local train travels at a speed of 60kmph, it reaches the destination on time. When the same train travels at speed of 50kmph, it reaches its destination 15 minutes late. What is the length of journey? A)75km b)50km c)60km d)85km ans. Let the time taken by a train to reach destination at 60kmph is x. Then it takes (x+15) at 50kmph. So distance, 60x=50(x+15) x=75option (a) is correct.When a local train travels at a speed of 60kmph, it reaches the destination on time. When the same train travels at speed of 50kmph, it reaches its destination 15 minutes late. What is the length of journey? A)75km b)50km c)60km d)85km ans. Let the time taken by a train to reach destination at 60kmph is x. Then it takes (x+15) at 50kmph. So distance, 60x=50(x+15) x=75option (a) is correct?
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Answer:
hey mate...... answer is already given in your question.... see the above image....
Explanation:
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Answered by
1
Answer:
75km
Explanation:
If t is the time , corresponding to 60km/h
60t = 50 ( t + 1/4)
10t = 50/4
60 t = 300/4 = 75 km
---------------------or------------------------------------
X= by
X = 60000/3600 t --------------'(1)
X =50000/3600 (t+900)--------(2)
By solving
t = 4500 s
Then substitute in eqn 1
X = 75 km
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