when a mass of 40 g is attached to a vertically hanging spring it extends by 0.4 cm. find force constant of the spring
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apply the formula...
F=-kl
k=F/l ,
k=mg/l
40×9.8/0.4×10^(-2) =98×10^(3) N/m .
F=-kl
k=F/l ,
k=mg/l
40×9.8/0.4×10^(-2) =98×10^(3) N/m .
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