when a metal cube is completely submerged in water contained in a cylindrical vessel with diameter 30 cm, the level of water rises by 1 and 41 by 99 cm find the length of the edge of the cube and TSA of the cube
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Given : Diameter of cylindrical vessel = 30 cm , So radius = 15 cm
And when cube submerged water level increase by 14199cm = 99 + 4199 = 14099cm
Let edge of cube = x and we know volume of cube = ( Edge )3 , So
Volume of given cube = x3
We know volume of cylinder = π r2 h , So
Volume of water = 227 × 152 × 14099 = 2 × 15 × 15× 209 = 2 × 5 × 5×20 = 1000 cm3
Here , when a cube is submerged into a cylindrical vessel, the volume of water displaced is equal to the volume of cube .
Therefore,
x3 = 1000
x3 = 103
x = 10
So,
Edge of cube = 10 cm ( Ans )
We know Total surface area of cube = 6 ( Edge )2
So,
Total surface area of given cube = 6 ( 10)2 = 6 ( 100 ) = 600 cm2 (ans)
hope it helps you
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And when cube submerged water level increase by 14199cm = 99 + 4199 = 14099cm
Let edge of cube = x and we know volume of cube = ( Edge )3 , So
Volume of given cube = x3
We know volume of cylinder = π r2 h , So
Volume of water = 227 × 152 × 14099 = 2 × 15 × 15× 209 = 2 × 5 × 5×20 = 1000 cm3
Here , when a cube is submerged into a cylindrical vessel, the volume of water displaced is equal to the volume of cube .
Therefore,
x3 = 1000
x3 = 103
x = 10
So,
Edge of cube = 10 cm ( Ans )
We know Total surface area of cube = 6 ( Edge )2
So,
Total surface area of given cube = 6 ( 10)2 = 6 ( 100 ) = 600 cm2 (ans)
hope it helps you
please mark it brainliest answer
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