Question

when a metal is burnt its weight increased by 24% the equivalent weight of the metal will be

Answer 1

"Equivalent weight of O^2-(oxide) ion is : Molar mass of oxygen/ charge of oxygen

= 16 g mol^-1 /2 mol eq^-1

= 8 g eq^-1

Let us consider M to be the equivalent weight of the metal.

Therefore when M grams of the metal will react with 8g of oxygen the corresponding metal oxide formed will be 8gm more in Mass. This 8 gram is 24% of M.

Or we can say that M x 24/100 = 8 gram

So, M = 100 x 8/24 = 33.33 g

"

Answer 2

Answer:

Equivalent weight of O2O2 (oxide) ion is:

Molar mass of oxygen / charge on oxygen

=16gmol−1/2moleq−1=16gmol−1/2moleq−1

=8geq−1=8geq−1

One equivalent of the metal reacts with one equivalent of oxygen to form the metal oxide.

Let M be the equivalent weight of the metal,

Therefore, M grams of the metal will react with 8g of oxygen.

The corresponding metal oxide will or wWe can say that,

M=100×824M=100×824=33.33g

Explanation: